¹²C₃ = 12!/(12-3)!3!
= 12.11.10.9!/9!3!
= 12.11.10/3.2
= 2.11.10
= 220
Peluang terambilnya 2 bola merah dan 1 bola biru
= ⁵C₂ . ⁴C₁ / ¹²C₃
= 10.4/220
= 40/220
= 4/22
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Kamis, 9 Mei 2024 -
Network
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Network
¹²C₃ = 12!/(12-3)!3!
= 12.11.10.9!/9!3!
= 12.11.10/3.2
= 2.11.10
= 220
Peluang terambilnya 2 bola merah dan 1 bola biru
= ⁵C₂ . ⁴C₁ / ¹²C₃
= 10.4/220
= 40/220
= 4/22
Editor: Mariyani Soetrisno
Sumber: Buku.kemdikbud.go.id
