Kunci Jawaban Matematika Kelas 9 Halaman 30, 31, 32 Semester 1 Latihan 1.3 Pembagian Perpangkatan

b. (-4)^6/(-4)^2
= (-4)^(6-2)
= (-4)^4
= 256.

c. 0,3^7/0,3^3
= (0,3)^(7-3)
= (0,3)^4
= 0,34
= 0,0081

d. (2/5)^9/(2/5)^5
= (2/5)^(9-5)
= (2/5)^4
= 16/625

e. (3^7 x 3^2)/3^3
= 3^(7+2)-3
= 3^6
= 729

f. 5^5/(5^2 x 5^3)
= 5^5 /5^(2+3)
= 5^(5-5)
= 5^0
- 1

g. (2^7 x 6^7)/4^7
= 2^7 x 2^7 x 3^7 / 4^7
= (2.2)^7 x 3^7/4^7
= 4^7-7 x 3^7
= 4^0 x 3^7
= 1 x 3^7
= 3^7

h. (6^7 x 3^3)/2^7
(2.3)^7 x 3^3/2^7
= 2^7 x 3^7 x 3^3/2^7
= 2^(7-7) x 3^(7+3)
= 2^0 x 3^10
= 1 x 3^10
= 3^10

Baca Juga: Kunci Jawaban IPA Kelas 9 Uji Kompetensi 1 Semester 1 Halaman 47 48 49: Sistem Reproduksi Manusia

i. (10^6 x 4^2)/(25^3 x 8^3)
= (2.5)6 x (2^2)2 / (5^2)3 x (2^3)^3
= 2^6 x 5^6 x 2^4 / 5^6 x 2^9
= 2^(6+4)-9 x 5^(6-6)
= 2^1 x 5^0
= 2 x 1
= 2

j. (21^5 : 9^2)/(7/2)2
= 21^5/9^2 x (2/7)2
= (3.7)^5/(3^2)2 x 2^2/7^2
= 3^5 x 7^5 x 2^2/ 3^4 x 7^2
= 3^(5-4) x 7^(5-2) x 2^2
= 3^1 x 7^3 x 2^2
= 3 x 4 x 7^3
= 12 x 7^3