Kunci Jawaban Matematika Kelas 9 Halaman 30 31 32: Cara Hitung Pembagian Pada Perpangkatan

a. (-y)^5/(-y)^2
= (-y)^(5-2)=3
= y^3

b. (1/t)^7/(1/t)^3
= (1/t)^7-3=4
= 1/t^7/1/t^3
= 1/t^7 . t^3/1
= t^3/t^7
= t^(3-7)
= 1/t^4

c. 3m^7/m^3
= 3m^(7-3)= 3m^4
= 3m^4

d. 42y^8/12y^5
= 42/12 . y^8/y^5
= (7/2)y^3

e. ((1/t)^7 : (1/t)^3) x ((1/t)^3 : (1/t)^2)
= 1/t^7/1/t^3 x 1/t^3/1/t^2
= 1/t^7/1/t^2
= 1/t^7 . t^2/1
= t^2/t^7
= t^(-5)
= 1/t^5

f. 3w^4/w^2 x 5w^3
= 3w^2 x 5w^3
= 15 w^5

Soal nomor 3

a. (0,2^4 x 0,2^2) : 0,2^5
= (0,2)^(4+2-5) = (0,2)^1
= (0,2)^1
= 1/5

b. (-5)^5: (-5)^2 x (-5)^2
= (-5)^(5-2+2) = 1
= (-5)^1
= -5

c. 12 + (4^7/4^6)
= 12 + 4^(7-6) = 1
= 12 + 4
= 16